Showing posts with label bpm. Show all posts
Showing posts with label bpm. Show all posts

Monday, November 16, 2015

Maximum Flow and BPM Problems from SPOJ and HDU


Here is a short list of network flow and bpm problems that I managed to solve from SPOJ and HDU. This is not much and there are other sources of these kinds of problems, but I think these are some good starting points. Also I did not classify them on the types of flow or bpm, that would be up to the reader.

Maximum Flow and Bipartite Matching problems from SPOJ

ANGELSBABYDIVRELFASTFLOWMATCHING
MSE06IMTOTALFMUDDYPCPC12HPROFIT
PT07XQUEST4SCITIESSTEADTAXI

Maximum Flow and Bipartite Matching problems from HDU

15321533185324482686
27322833308132773315
33763395341634193435
34683472348834913572
36673987399841834309

Note: UVa has a lot of flow and bpm problems, please visit uHunt for guidelines.

Note: It is very possible that there are many other problems from these online judges which can be solved by flow or bpm algorithms. And, some problems here could be mistakenly added as flow or bpm category due to copy paste errors. Please feel free to leave a note on the comment section, add more links if you like to. Happy coding \m/


Saturday, May 22, 2010

Maximum Matching (DFS)



Maximum bipartite matching in a bipartite graph


Although Hopcroft Karp is faster and smarter, this one is pretty simple to code specially in contest time and when the graph is relatively smaller. It uses a DFS subroutine to cut and establish matching and thus produces a maximum matching. This version of BPM takes the adjacency list of left side of the bipartite graph and updates the Left[] and Right[] arrays with their respective matches.

Here, in the DFS subroutine, there are two for loops, where, the first one checks for yet unestablished connections, and the second one is the recursive DFS step. These two steps could be written in a single loop and the condition modified as "( Right[v]==-1 || dfs(Right[v]) )", actually separating them increases performance by some factors, because, first time it checks all the unmatched nodes before going into DFS.

A sample C++ implementation:

#define SET(x) memset(x, -1, sizeof(x))
#define CLR(x) memset(x, 0, sizeof(x))
#define MAX 100

vector < int > edges[MAX];
bool visited[MAX];
int Left[MAX], Right[MAX];

bool dfs(int u) {
if(visited[u]) return false;
visited[u] = true;
int len = edges[u].size(), i, v;
for(i=0; i<len; i++) {
v = edges[u][i];
if(Right[v]==-1) {
Right[v] = u, Left[u] = v;
return true;
}
}
for(i=0; i<len; i++) {
v = edges[u][i];
if(dfs(Right[v])) {
Right[v] = u, Left[u] = v;
return true;
}
}
return false;
}

int match() {
SET(Left);
SET(Right);
int i, ret = 0;
bool done;
do {
done = true;
CLR(visited);
for(i=0; i<MAX; i++) {
if(Left[i]==-1 && dfs(i)) {
done = false;
}
}
} while(!done);
for(i=0; i<MAX; i++) ret += (Left[i]!=-1);
return ret;
}

Notes: Here, edges[MAX] is the left side adjacency list, implemented with vector, Left[MAX] and Right[MAX] holds the matching and the procedure match() returns maximum matching. Pretty straight forward.

Friday, May 7, 2010

Maximum Matching (Hopcroft)



Hopcroft-Karp is one of the fastest algorithm that finds the maximum cardinality matching on a bipartite graph. It has the best known worst case time complexity. More details can be found here [courtesy of Wikipedia].

C++ Source Code:



#define MAX 100001
#define NIL 0
#define INF (1<<28)

vector< int > G[MAX];
int n, m, match[MAX], dist[MAX];
// n: number of nodes on left side, nodes are numbered 1 to n
// m: number of nodes on right side, nodes are numbered n+1 to n+m
// G = NIL[0] ∪ G1[G[1---n]] ∪ G2[G[n+1---n+m]]

bool bfs() {
int i, u, v, len;
queue< int > Q;
for(i=1; i<=n; i++) {
if(match[i]==NIL) {
dist[i] = 0;
Q.push(i);
}
else dist[i] = INF;
}
dist[NIL] = INF;
while(!Q.empty()) {
u = Q.front(); Q.pop();
if(u!=NIL) {
len = G[u].size();
for(i=0; i<len; i++) {
v = G[u][i];
if(dist[match[v]]==INF) {
dist[match[v]] = dist[u] + 1;
Q.push(match[v]);
}
}
}
}
return (dist[NIL]!=INF);
}

bool dfs(int u) {
int i, v, len;
if(u!=NIL) {
len = G[u].size();
for(i=0; i<len; i++) {
v = G[u][i];
if(dist[match[v]]==dist[u]+1) {
if(dfs(match[v])) {
match[v] = u;
match[u] = v;
return true;
}
}
}
dist[u] = INF;
return false;
}
return true;
}

int hopcroft_karp() {
int matching = 0, i;
// match[] is assumed NIL for all vertex in G
while(bfs())
for(i=1; i<=n; i++)
if(match[i]==NIL && dfs(i))
matching++;
return matching;
}

The implementation is quite straight forward as the algorithm on Wikipedia page. I am looking for some optimizations.